Match List-$I$ with List-$II$ :
$LIST$-$I$ (Hybridization) $LIST$-$II$ (Orientation in Space) $A$. $sp^3$ $I$. Trigonal bipyramidal $B$. $dsp^2$ $II$. Octahedral $C$. $sp^3 d$ $III$. Tetrahedral $D$. $sp^3 d^2$ $IV$. Square planar
Choose the correct answer from the options given below :
| $LIST$-$I$ (Hybridization) | $LIST$-$II$ (Orientation in Space) |
| $A$. $sp^3$ | $I$. Trigonal bipyramidal |
| $B$. $dsp^2$ | $II$. Octahedral |
| $C$. $sp^3 d$ | $III$. Tetrahedral |
| $D$. $sp^3 d^2$ | $IV$. Square planar |
Choose the correct answer from the options given below :
- A$A-III, B-I, C-IV, D-II$
- B$A-II, B-I, C-IV, D-III$
- C$A-IV, B-III, C-I, D-II$
- D$A-III, B-IV, C-I, D-II$
Explore More
Similar Questions
In which of the following species is the hybrid state of the central atom the same?
Difficult
View SolutionWhich compound does not possess linear geometry?
Medium
View SolutionIn which of the following molecular shapes must the $d_{z^2}$ orbital not be involved in bonding?
Difficult
View SolutionChoose the molecules in which hybridization occurs in the ground state?
$(i)$ $BCl_3$ $(ii)$ $NH_3$
$(iii)$ $PCl_3$ $(iv)$ $BeF_2$
The correct answer is
$(i)$ $BCl_3$ $(ii)$ $NH_3$
$(iii)$ $PCl_3$ $(iv)$ $BeF_2$
The correct answer is
Medium
View SolutionWhich of the underlined atoms in the molecules shown below have $sp$-hybridization?
$(u) H_2\underline{C}=CH-CH_3$
$(v) CH_2=\underline{C}=CHCl$
$(w) CH_3-\underline{C}H_2^+$
$(x) H-C \equiv C-H$
$(y) CH_3-\underline{C} \equiv N$
$(z) (CH_3)_2C=\underline{N}-NH_2$
$(u) H_2\underline{C}=CH-CH_3$
$(v) CH_2=\underline{C}=CHCl$
$(w) CH_3-\underline{C}H_2^+$
$(x) H-C \equiv C-H$
$(y) CH_3-\underline{C} \equiv N$
$(z) (CH_3)_2C=\underline{N}-NH_2$
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo