Match List-I with List-II.

List- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $(A) [MnBr_4]^{2-}$: $Mn^{2+}$ is $[Ar] 3d^5$. $Br^-$ is a weak field ligand,so it undergoes $sp^3$ hybridization and is paramagnetic.
$(B) [FeF_

Vedclass · Accepted Answer

$A-IV, B-II, C-I, D-III$

Vedclass · Answer

(D) $(A) [MnBr_4]^{2-}$: $Mn^{2+}$ is $[Ar] 3d^5$. $Br^-$ is a weak field ligand,so it undergoes $sp^3$ hybridization and is paramagnetic.
$(B) [FeF_6]^{3-}$: $Fe^{3+}$ is $[Ar] 3d^5$. $F^-$ is a weak field ligand,so it undergoes $sp^3d^2$ hybridization and is paramagnetic.
$(C) [Co(C_2O_4)_3]^{3-}$: $Co^{3+}$ is $[Ar] 3d^6$. $C_2O_4^{2-}$ is a strong field ligand,so it undergoes $d^2sp^3$ hybridization and is diamagnetic.
$(D) [Ni(CO)_4]$: $Ni^0$ is $[Ar] 3d^8 4s^2$. $CO$ is a strong field ligand,so it undergoes $sp^3$ hybridization and is diamagnetic.
Therefore,the correct matching is $A-IV, B-II, C-I, D-III$.

List-$I$	List-$II$
$A$. $[MnBr_4]^{2-}$	$I$. $d^2sp^3$ and diamagnetic
$B$. $[FeF_6]^{3-}$	$II$. $sp^3d^2$ and paramagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$	$III$. $sp^3$ and diamagnetic
$D$. $[Ni(CO)_4]$	$IV$. $sp^3$ and paramagnetic

Column $I$	Column $II$
$(A)$ $sp^3$	$(i)$ $[Co(NH_3)_6]^{3+}$
$(B)$ $dsp^2$	$(ii)$ $[Ni(CO)_4]$
$(C)$ $sp^3d^2$	$(iii)$ $[Pt(NH_3)_2Cl_2]$
$(D)$ $d^2sp^3$	$(iv)$ $[CoF_6]^{3-}$
	$(v)$ $[Fe(CO)_5]$

Similar Questions

Reaction of $[Co(H_2O)_6]^{2+}$ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in $t_{2g}$-orbitals of the product is $.....$ .

The hybridization of the central metal ion in $[CoF_6]^{3-}$ is ....

The species having tetrahedral shape is

For which of the following $d^n$ configurations of octahedral complexes,can they $NOT$ exist in both high spin and low spin forms?
$(I)$ $d^3$,$(II)$ $d^5$,$(III)$ $d^6$,$(IV)$ $d^8$

Vedclass Test Series

Exam Paper Generator

Online Exam Module