Match List-I with List-II: List-I (Compl | vedclass

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Question

(A) Primary valency is equal to the oxidation state of the central metal atom.Secondary valency is equal to the coordination number of the central met

Vedclass · Accepted Answer

$A-I, B-II, C-III, D-IV$

Vedclass · Answer

(A) Primary valency is equal to the oxidation state of the central metal atom.Secondary valency is equal to the coordination number of the central metal atom.$1$. $[Co(en)_2 Cl_2] Cl$: $Co$ is in $+3$ state,$CN = 2(2) + 2 = 6$. So,$(A-I)$.$2$. $[Pt(NH_3)_2 Cl(NO_2)]$: $Pt$ is in $+2$ state,$CN = 2 + 1 + 1 = 4$. So,$(B-II)$.$3$. $Hg[Co(SCN)_4]$: $Co$ is in $+3$ state (considering $Hg^{2+}$),$CN = 4$. So,$(C-III)$.$4$. $[Mg(EDTA)]^{2-}$: $Mg$ is in $+2$ state,$EDTA$ is hexadentate,$CN = 6$. So,$(D-IV)$.Thus,the correct match is $A-I, B-II, C-III, D-IV$.

List-$I$ (Complex)	List-$II$ (Primary valency and Secondary valency)
$(A)$ $[Co(en)_2 Cl_2] Cl$	$(I)$ $3, 6$
$(B)$ $[Pt(NH_3)_2 Cl(NO_2)]$	$(II)$ $2, 4$
$(C)$ $Hg[Co(SCN)_4]$	$(III)$ $3, 4$
$(D)$ $[Mg(EDTA)]^{2-}$	$(IV)$ $2, 6$

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