Match List-$I$ with List-$II$.
List-$I$ (Functional group detection)List-$II$ (Change observed during detection)
$A$. Unsaturation (Baeyer's test)$I$. Red colour appears
$B$. Alcoholic group (Ceric ammonium nitrate test)$II$. Silver mirror appears
$C$. Aldehyde group (Tollen's reagent)$III$. Violet colour appears
$D$. Phenolic group ($FeCl_3$ test)$IV$. Discharge of pink colour

Choose the correct answer from the options given below:

  • A
    $A-III, B-IV, C-II, D-I$
  • B
    $A-III, B-IV, C-I, D-II$
  • C
    $A-IV, B-III, C-II, D-I$
  • D
    $A-IV, B-III, C-I, D-II$

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Similar Questions

Which of the following substances will give the Lassaigne's test for nitrogen?

Match Column $-I$ with Column $-II$.
Column $-I$ Column $-II$
$(A).$ Dumas method $(3).$ Nitrogen gas
$(B).$ Kjeldahl's method $(5).$ Ammonium sulphate
$(C).$ Carius method $(1).$ $AgNO_3$
$(D).$ Chromatography $(2).$ Silica gel
$(E).$ Homolytic fission $(4).$ Free radical

How are carbon and hydrogen detected in an organic compound? Explain with reactions.

Sodium extract is heated with concentrated $HNO_3$ before testing for halogens because

Match List-$I$ with List-$II$:
List-$I$ (Test/Reagents/Observation) List-$II$ (Species detected)
$(a)$ Lassaigne's Test $(i)$ Carbon
$(b)$ $Cu(II)$ oxide $(ii)$ Sulphur
$(c)$ Silver nitrate $(iii)$ $N, S, P,$ and halogen
$(d)$ The sodium fusion extract gives black precipitate with acetic acid and lead acetate $(iv)$ Halogen specifically

The correct match is:

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