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(D) The crystal field splitting energy ($\Delta_o$) depends on the strength of the ligand according to the spectrochemical series.
The spectrochemica

Vedclass · Accepted Answer

$A-IV, B-I, C-II, D-III$

Vedclass · Answer

(D) The crystal field splitting energy ($\Delta_o$) depends on the strength of the ligand according to the spectrochemical series.
The spectrochemical series order for the given ligands is: $F^- < H_2O < en < CN^-$.
As the ligand field strength increases, the value of $\Delta_o$ increases.
Therefore, the order of $\Delta_o$ values is: $[CrF_6]^{3-} < [Cr(H_2O)_6]^{3+} < [Cr(en)_3]^{3+} < [Cr(CN)_6]^{3-}$.
Matching the values:
$A$. $[Cr(CN)_6]^{3-}$ corresponds to $IV$ ($26,600$ $cm^{-1}$).
$B$. $[CrF_6]^{3-}$ corresponds to $I$ ($15,060$ $cm^{-1}$).
$C$. $[Cr(H_2O)_6]^{3+}$ corresponds to $II$ ($17,400$ $cm^{-1}$).
$D$. $[Cr(en)_3]^{3+}$ corresponds to $III$ ($22,300$ $cm^{-1}$).
Thus, the correct match is $A-IV, B-I, C-II, D-III$.

Similar Questions

Arrange the following in increasing order of their crystal field splitting energy:
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$IV. [CoF_6]^{3-}$

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