(C) Siderite is $FeCO_{3}$,which is an ore of $Fe$.$(b)$ Calamine is $ZnCO_{3}$,which is an ore of $Zn$.$(c)$ Malachite is $Cu(OH)_{2} \cdot CuCO_{3}$

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$(a)$ $\rightarrow (iii), (b)$ $\rightarrow (v), (c)$ $\rightarrow (i), (d)$ $\rightarrow (iv)$

(C) Siderite is $FeCO_{3}$,which is an ore of $Fe$.$(b)$ Calamine is $ZnCO_{3}$,which is an ore of $Zn$.$(c)$ Malachite is $Cu(OH)_{2} \cdot CuCO_{3}$,which is an ore of $Cu$.$(d)$ Cryolite is $Na_{3}AlF_{6}$,which is an ore of $Al$.Therefore,the correct matching is: $(a)$ $\rightarrow (iii), (b)$ $\rightarrow (v), (c)$ $\rightarrow (i), (d)$ $\rightarrow (iv)$.

Class 12 Chemistry General Principles and Processes of Isolation of Elements Occurrence

Easy

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$(a)$ Siderite $(i)$ $Cu$

$(b)$ Calamine $(ii)$ $Ca$

$(c)$ Malachite $(iii)$ $Fe$

$(d)$ Cryolite $(iv)$ $Al$

$(v)$ $Zn$

Choose the correct answer from the options given below:

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A
$(a)$ $\rightarrow (iii), (b)$ $\rightarrow (i), (c)$ $\rightarrow (v), (d)$ $\rightarrow (ii)$
B
$(a)$ $\rightarrow (i), (b)$ $\rightarrow (ii), (c)$ $\rightarrow (v), (d)$ $\rightarrow (iii)$
C
$(a)$ $\rightarrow (iii), (b)$ $\rightarrow (v), (c)$ $\rightarrow (i), (d)$ $\rightarrow (iv)$
D
$(a)$ $\rightarrow (i), (b)$ $\rightarrow (ii), (c)$ $\rightarrow (iii), (d)$ $\rightarrow (iv)$