Match List-$I$ with List-$II$.
List-$I$ (Oxide) List-$II$ (Nature)
$A. Cl_2O_7$ $I. Amphoteric$
$B. Na_2O$ $II. Basic$
$C. Al_2O_3$ $III. Neutral$
$D. N_2O$ $IV. Acidic$

Choose the correct answer from the options given below:

  • A
    $A-IV, B-II, C-I, D-III$
  • B
    $A-IV, B-II, C-I, D-III$
  • C
    $A-II, B-IV, C-III, D-I$
  • D
    $A-I, B-II, C-III, D-IV$

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$2$. $Cl$ is more electronegative than $S$.
$3$. $HClO_4$ is monobasic,whereas $H_2SO_4$ is dibasic.
$4$. $ClO_3$ part of $HClO_4$ can break $O-H$ bond more easily to liberate a proton than $SO_3$ part in $H_2SO_4$.

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