Match List-$I$ with List-$II$:
List-$I$ List-$II$ $(A)$ $3$ Translational degrees of freedom $(I)$ Monoatomic gases $(B)$ $3$ Translational,$2$ rotational degrees of freedom $(III)$ Rigid diatomic gases $(C)$ $3$ Translational,$2$ rotational and $1$ vibrational degrees of freedom $(IV)$ Non-rigid diatomic gases $(D)$ $3$ Translational,$3$ rotational and more than one vibrational degrees of freedom $(II)$ Polyatomic gases
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $(A)$ $3$ Translational degrees of freedom | $(I)$ Monoatomic gases |
| $(B)$ $3$ Translational,$2$ rotational degrees of freedom | $(III)$ Rigid diatomic gases |
| $(C)$ $3$ Translational,$2$ rotational and $1$ vibrational degrees of freedom | $(IV)$ Non-rigid diatomic gases |
| $(D)$ $3$ Translational,$3$ rotational and more than one vibrational degrees of freedom | $(II)$ Polyatomic gases |
Choose the correct answer from the options given below:
- A$(A) - (IV), (B) - (III), (C) - (II), (D) - (I)$
- B$(A) - (IV), (B) - (II), (C) - (I), (D) - (III)$
- C$(A) - (I), (B) - (III), (C) - (IV), (D) - (II)$
- D$(A) - (I), (B) - (IV), (C) - (III), (D) - (II)$
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DifficultNEET 2026
View SolutionThe number of rotational degrees of freedom of a monatomic molecule is
$Assertion :$ For a gas atom,the number of degrees of freedom is $3$.
$Reason :$ $\frac{C_P}{C_V} = \gamma $
$Reason :$ $\frac{C_P}{C_V} = \gamma $
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