Match the text{LIST-I} with text{LIST-II}: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Boltzmann constant $(k)$: $k = \frac{PV}{NT}$. Dimensional formula $[k] = \frac{[ML^2 T^{-2}]}{[K]} = ML^2 T^{-2} K^{-1}$. (Matches $III$)$(B)$ Co

Vedclass · Accepted Answer

$A-III, B-IV, C-I, D-II$

Vedclass · Answer

(A) Boltzmann constant $(k)$: $k = \frac{PV}{NT}$. Dimensional formula $[k] = \frac{[ML^2 T^{-2}]}{[K]} = ML^2 T^{-2} K^{-1}$. (Matches $III$)$(B)$ Coefficient of viscosity $(\eta)$: $F = 6\pi \eta rv$. Dimensional formula $[\eta] = \frac{[F]}{[r][v]} = \frac{[MLT^{-2}]}{[L][LT^{-1}]} = ML^{-1} T^{-1}$. (Matches $IV$)$(C)$ Planck's constant $(h)$: $E = hf$. Dimensional formula $[h] = \frac{[E]}{[f]} = \frac{[ML^2 T^{-2}]}{[T^{-1}]} = ML^2 T^{-1}$. (Matches $I$)$(D)$ Thermal conductivity $(k)$: $\frac{dQ}{dt} = k A \frac{dT}{dx}$. Dimensional formula $[k] = \frac{[ML^2 T^{-3}][L]}{[L^2][K]} = MLT^{-3} K^{-1}$. (Matches $II$)Therefore,the correct matching is $A-III, B-IV, C-I, D-II$.

$\text{LIST-I}$	$\text{LIST-II}$
$A$. Boltzmann constant	$I$. $ML^2 T^{-1}$
$B$. Coefficient of viscosity	$II$. $MLT^{-3} K^{-1}$
$C$. Planck's constant	$III$. $ML^2 T^{-2} K^{-1}$
$D$. Thermal conductivity	$IV$. $ML^{-1} T^{-1}$

List-$I$	List-$II$
$(A)$ Young's Modulus	$(I)$ $[ML^{-1}T^{-1}]$
$(B)$ Torque	$(II)$ $[ML^{-1}T^{-2}]$
$(C)$ Coefficient of Viscosity	$(III)$ $[M^{-1}L^3T^{-2}]$
$(D)$ Gravitational Constant	$(IV)$ $[ML^2T^{-2}]$

Similar Questions

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$(A)$ Young's Modulus $(I)$ $[ML^{-1}T^{-1}]$
$(B)$ Torque $(II)$ $[ML^{-1}T^{-2}]$
$(C)$ Coefficient of Viscosity $(III)$ $[M^{-1}L^3T^{-2}]$
$(D)$ Gravitational Constant $(IV)$ $[ML^2T^{-2}]$

Choose the correct answer from the options given below:

Identify the physical parameters from the list given below that have the same dimensions:
$(i)$ Magnetic field $(B)$
$(ii)$ Energy density $(u)$
$(iii)$ Refractive index $(\mu)$
$(iv)$ Young's modulus $(Y)$
$(v)$ Dielectric constant $(K)$

The fundamental unit which has the same power in the dimensional formula of surface tension and viscosity is

Identify the pair of physical quantities which have different dimensions.

Which one has dimensions different from the remaining three?

Vedclass Test Series

Exam Paper Generator

Online Exam Module