Match the following columns :- Column-I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The correct matches based on the genetic material content are as follows:$1$. $\phi 	imes 174$ bacteriophage has $5386$ nucleotides (bases) - $(a

Vedclass · Accepted Answer

$a-ii, b-iii, c-iv, d-i$

Vedclass · Answer

(C) The correct matches based on the genetic material content are as follows:$1$. $\phi 	imes 174$ bacteriophage has $5386$ nucleotides (bases) - $(a-ii)$.$2$. Human (diploid) $DNA$ content is $6.6 	imes 10^9$ base pairs (b.p) - $(b-iii)$.$3$. $E. coli$ has $4.6 	imes 10^6$ base pairs (b.p) - $(c-iv)$.$4$. $\lambda$-phage has $48502$ base pairs (b.p) - $(d-i)$.Therefore,the correct sequence is $a-ii, b-iii, c-iv, d-i$.

Column-$I$	Column-$II$
$(a)$ $\phi \times 174$ bacteriophage	$(i)$ $48502 \ \text{b.p}$
$(b)$ Human (diploid)	$(ii)$ $5386$ bases
$(c)$ $E. coli$	$(iii)$ $6.6 \times 10^9 \ \text{b.p}$
$(d)$ $\lambda$-phage	$(iv)$ $4.6 \times 10^6 \ \text{b.p}$

Match the following columns $:-$

Column-$I$ Column-$II$

$(a)$ $\phi \times 174$ bacteriophage $(i)$ $48502 \ \text{b.p}$

$(b)$ Human (diploid) $(ii)$ $5386$ bases

$(c)$ $E. coli$ $(iii)$ $6.6 \times 10^9 \ \text{b.p}$

$(d)$ $\lambda$-phage $(iv)$ $4.6 \times 10^6 \ \text{b.p}$

Similar Questions

How many base pairs of $DNA$ are wrapped around a histone octamer?

$A$ single-stranded $DNA$ molecule is the genetic material of which bacteriophage?

If the length of $E. \; coli$ $DNA$ is $1.36 \; mm$, calculate the number of base pairs in $E. \; coli$.

The amount of $DNA$ in the inactive region is ......

$A$ polymer of deoxyribonucleotides is known as - ........

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the following columns $:-$ Column-$I$ Column-$II$ $(a)$ $\phi \times 174$ bacteriophage $(i)$ $48502 \ \text{b.p}$ $(b)$ Human (diploid) $(ii)$ $5386$ bases $(c)$ $E. coli$ $(iii)$ $6.6 \times 10^9 \ \text{b.p}$ $(d)$ $\lambda$-phage $(iv)$ $4.6 \times 10^6 \ \text{b.p}$