Match the following polymers in List-I with t | vedclass

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Question

(NONE) The correct matches are:$(A)$ $-(NH-(CH_2)_6-NH-CO-(CH_2)_4-CO)_n-$ is Nylon-$6,6$,which is formed from Hexamethylene diamine and Adipic acid.

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$IV, III, V, I$

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(NONE) The correct matches are:$(A)$ $-(NH-(CH_2)_6-NH-CO-(CH_2)_4-CO)_n-$ is Nylon-$6,6$,which is formed from Hexamethylene diamine and Adipic acid. So,$A \rightarrow IV$.$(B)$ $-(CO-(CH_2)_5-NH)_n-$ is Nylon-$6$,which is formed from Caprolactam. So,$B \rightarrow III$.$(C)$ $-(CF_2-CF_2)_n-$ is Teflon,which is formed from Tetrafluoroethene. So,$C \rightarrow V$.$(D)$ $-(O-CH_2-CH_2-OOC-C_6H_4-CO)_n-$ is Dacron (Terylene),which is formed from Ethylene glycol and Terephthalic acid. So,$D \rightarrow I$.Thus,the correct sequence is $A-IV, B-III, C-V, D-I$.

List-$I$	List-$II$
$(A)$ $-(NH-(CH_2)_6-NH-CO-(CH_2)_4-CO)_n-$	$(I)$ Ethylene glycol and terephthalic acid
$(B)$ $-(CO-(CH_2)_5-NH)_n-$	$(II)$ Phenol and formaldehyde
$(C)$ $-(CF_2-CF_2)_n-$	$(III)$ Caprolactam
$(D)$ $-(O-CH_2-CH_2-OOC-C_6H_4-CO)_n-$	$(IV)$ Hexamethylene diamine and adipic acid
	$(V)$ Tetrafluoroethene

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