Match the following reactions in Column-$1$ with their main products in Column-$2$.
Column-$1$ (Reaction) Column-$2$ (Main product) $A$. $B_2H_6 + 2CO \longrightarrow$ $I$. $B_2O_3$ $B$. $B_2H_6 + 3O_2 \longrightarrow$ $II$. $2BH_3 \cdot CO$ $C$. $B_2H_6 + 6H_2O \longrightarrow$ $III$. $2H_3BO_3$
The correct match is:
| Column-$1$ (Reaction) | Column-$2$ (Main product) |
|---|---|
| $A$. $B_2H_6 + 2CO \longrightarrow$ | $I$. $B_2O_3$ |
| $B$. $B_2H_6 + 3O_2 \longrightarrow$ | $II$. $2BH_3 \cdot CO$ |
| $C$. $B_2H_6 + 6H_2O \longrightarrow$ | $III$. $2H_3BO_3$ |
The correct match is:
- A$A-IV, B-I, C-III$
- B$A-II, B-III, C-V$
- C$A-IV, B-III, C-I$
- D$A-II, B-I, C-III$
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Similar Questions
In the reactions $I$ and $II$,the covalencies of $Be$ and $Al$ in $X$ and $Y$ are respectively:
$I$ $Be(OH)_2 + NaOH \text{ (excess)} \rightarrow X$
$II$ $Al(OH)_3 + NaOH \text{ (excess)} \rightarrow Y$
$I$ $Be(OH)_2 + NaOH \text{ (excess)} \rightarrow X$
$II$ $Al(OH)_3 + NaOH \text{ (excess)} \rightarrow Y$
Consider the compounds,$BCl_3$ and $CCl_4$. How will they behave with water? Justify.
Easy
View SolutionGiven below are two statements:
Statement $I$: Boron is extremely hard,indicating its high lattice energy.
Statement $II$: Boron has the highest melting and boiling point compared to its other group members.
In the light of the above statements,choose the most appropriate answer from the options given below:
Statement $I$: Boron is extremely hard,indicating its high lattice energy.
Statement $II$: Boron has the highest melting and boiling point compared to its other group members.
In the light of the above statements,choose the most appropriate answer from the options given below:
Select the incorrect statement:
$a$. $PCl_5$ forms a weak monobasic acid during hydrolysis.
$b$. In $B_3N_3H_6$,nucleophilic attack occurs on the $B$ atom.
$c$. $Al_2Cl_6$ is a polar and planar molecule.
$d$. In $AlF_3$,the hybridization of $Al$ is $sp^2$.
$a$. $PCl_5$ forms a weak monobasic acid during hydrolysis.
$b$. In $B_3N_3H_6$,nucleophilic attack occurs on the $B$ atom.
$c$. $Al_2Cl_6$ is a polar and planar molecule.
$d$. In $AlF_3$,the hybridization of $Al$ is $sp^2$.
Difficult
View SolutionThe type of hybridisation of boron in diborane is
Easy
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