Match the following reactions of benzene diaz | vedclass

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Question

(A) The reactions of benzene diazonium chloride $(ArN_2^{+} Cl^{-})$ are as follows:$(A)$ Hydrolysis with $H_2O$ yields phenol $(ArOH)$. Thus,$(A) - (

Vedclass · Accepted Answer

$A-q, B-p, C-s, D-r$

Vedclass · Answer

(A) The reactions of benzene diazonium chloride $(ArN_2^{+} Cl^{-})$ are as follows:$(A)$ Hydrolysis with $H_2O$ yields phenol $(ArOH)$. Thus,$(A) - (q)$.$(B)$ Reaction with $HBF_4$ followed by $NaNO_2$ and heating yields nitrobenzene $(ArNO_2)$. Thus,$(B) - (p)$.$(C)$ Reduction with ethanol $(CH_3CH_2OH)$ yields benzene $(ArH)$. Thus,$(C) - (s)$.$(D)$ Balz-Schiemann reaction with $HBF_4$ followed by heating yields fluorobenzene $(ArF)$. Thus,$(D) - (r)$.Therefore,the correct matching is $A-q, B-p, C-s, D-r$.

Column-$I$	Column-$II$
$(A)$ $ArN_2^{+} Cl^{-} \rightarrow ArOH$	$(p)$ $HBF_4 / NaNO_2, \Delta$
$(B)$ $ArN_2^{+} Cl^{-} \rightarrow ArNO_2$	$(q)$ $H_2 O$
$(C)$ $ArN_2^{+} Cl^{-} \rightarrow ArH$	$(r)$ $HBF_4, \Delta$
$(D)$ $ArN_2^{+} Cl^{-} \rightarrow ArF$	$(s)$ $CH_3CH_2OH$

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