Match the following types of hydrides in List | vedclass

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(B) The correct matching is as follows:$(A)$ Electron precise hydrides have the exact number of electrons needed to form covalent bonds. These are for

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$A-(i), B-(iii), C-(iv), D-(ii)$

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(B) The correct matching is as follows:$(A)$ Electron precise hydrides have the exact number of electrons needed to form covalent bonds. These are formed by group $14$ elements such as $CH_4$ and $SiH_4$. Thus,$A-(i)$.$(B)$ Saline hydrides (also known as ionic hydrides) are compounds formed between hydrogen and the most active metals,especially alkali and alkaline-earth metals such as $MgH_2$. Thus,$B-(iii)$.$(C)$ Electron-deficient hydrides are compounds in which the central atom has an incomplete octet,such as boron in $B_2H_6$. Thus,$C-(iv)$.$(D)$ Electron-rich hydrides have one or more lone pairs of electrons around the central more electronegative element,such as $H_2O$. Thus,$D-(ii)$.Therefore,the correct match is $A-(i), B-(iii), C-(iv), D-(ii)$.

List-$I$ (Type of hydride)	List-$II$ (Example)
$(A)$ Electron precise	$(i)$ $SiH_4$
$(B)$ Saline	$(ii)$ $H_2O$
$(C)$ Electron deficient	$(iii)$ $MgH_2$
$(D)$ Electron rich	$(iv)$ $B_2H_6$

Match the following types of hydrides in List-$I$ with their examples in List-$II$.
List-$I$ (Type of hydride) List-$II$ (Example)
$(A)$ Electron precise $(i)$ $SiH_4$
$(B)$ Saline $(ii)$ $H_2O$
$(C)$ Electron deficient $(iii)$ $MgH_2$
$(D)$ Electron rich $(iv)$ $B_2H_6$

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Match the following types of hydrides in List-$I$ with their examples in List-$II$.List-$I$ (Type of hydride)List-$II$ (Example)$(A)$ Electron precise$(i)$ $SiH_4$$(B)$ Saline$(ii)$ $H_2O$$(C)$ Electron deficient$(iii)$ $MgH_2$$(D)$ Electron rich$(iv)$ $B_2H_6$