Match the following: List-I (Molecule) | vedclass

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(A) $XeF_4$: Central atom $Xe$ has $4$ bond pairs and $2$ lone pairs,resulting in square planar geometry $(III)$.$ClF_3$: Central atom $Cl$ has $3$ bo

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$A-III, B-IV, C-I, D-II$

Vedclass · Answer

(A) $XeF_4$: Central atom $Xe$ has $4$ bond pairs and $2$ lone pairs,resulting in square planar geometry $(III)$.$ClF_3$: Central atom $Cl$ has $3$ bond pairs and $2$ lone pairs,resulting in bent $T$-shape geometry $(IV)$.$BrF_5$: Central atom $Br$ has $5$ bond pairs and $1$ lone pair,resulting in square pyramidal geometry $(I)$.$IF_7$: Central atom $I$ has $7$ bond pairs and $0$ lone pairs,resulting in pentagonal bipyramidal geometry $(II)$.Therefore,the correct match is $A-III, B-IV, C-I, D-II$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $XeF_4$	$I$. Square pyramidal
$B$. $ClF_3$	$II$. Pentagonal bipyramidal
$C$. $BrF_5$	$III$. Square planar
$D$. $IF_7$	$IV$. Bent $T$-shape

Match the following:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $XeF_4$ $I$. Square pyramidal

$B$. $ClF_3$ $II$. Pentagonal bipyramidal

$C$. $BrF_5$ $III$. Square planar

$D$. $IF_7$ $IV$. Bent $T$-shape

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Match the following: List-$I$ (Molecule) List-$II$ (Shape) $A$. $XeF_4$ $I$. Square pyramidal $B$. $ClF_3$ $II$. Pentagonal bipyramidal $C$. $BrF_5$ $III$. Square planar $D$. $IF_7$ $IV$. Bent $T$-shape