Match the following:Column-IColumn-II(a) Nucl | vedclass

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Question

(B) The correct matching is as follows:$(a)$ Nuclease acts on nucleic acids to break them down into nucleotides. Thus, $(a - iii)$.$(b)$ Nucleotidases

Vedclass · Accepted Answer

$(a - iii), (b - iv), (c - i), (d - ii)$

Vedclass · Answer

(B) The correct matching is as follows:$(a)$ Nuclease acts on nucleic acids to break them down into nucleotides. Thus, $(a - iii)$.$(b)$ Nucleotidases act on nucleotides to break them down into nucleosides and inorganic phosphate. Thus, $(b - iv)$.$(c)$ Nucleosidases act on nucleosides to break them down into sugars and nitrogenous bases. Thus, $(c - i)$.$(d)$ Lipases act on fats to break them down into monoglycerides and fatty acids. Thus, $(d - ii)$.Therefore, the correct sequence is $(a - iii), (b - iv), (c - i), (d - ii)$.

Column-$I$	Column-$II$
$(a)$ Nuclease	$(i)$ Nucleotide
$(b)$ Nucleotidases	$(ii)$ Monoglycerides
$(c)$ Nucleosidases	$(iii)$ Nucleic acid
$(d)$ Lipases	$(iv)$ Nucleoside

Match the following:
Column-$I$ Column-$II$
$(a)$ Nuclease $(i)$ Nucleotide
$(b)$ Nucleotidases $(ii)$ Monoglycerides
$(c)$ Nucleosidases $(iii)$ Nucleic acid
$(d)$ Lipases $(iv)$ Nucleoside

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Match the following:Column-$I$Column-$II$$(a)$ Nuclease$(i)$ Nucleotide$(b)$ Nucleotidases$(ii)$ Monoglycerides$(c)$ Nucleosidases$(iii)$ Nucleic acid$(d)$ Lipases$(iv)$ Nucleoside