Match the following:List-I (Amine)List-II (pK | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The basicity of amines is inversely proportional to their $pK_b$ values. $A$ lower $pK_b$ value indicates a stronger base.$1$. $N$-Ethylethanamine

Vedclass · Accepted Answer

$A-II, B-III, C-IV, D-I$

Vedclass · Answer

(A) The basicity of amines is inversely proportional to their $pK_b$ values. $A$ lower $pK_b$ value indicates a stronger base.$1$. $N$-Ethylethanamine (diethylamine) is an aliphatic secondary amine,which is much more basic than aromatic amines due to the absence of resonance stabilization of the lone pair on nitrogen. Thus,it has the lowest $pK_b$ value: $C-IV$ $(3.00)$.$2$. Among the aromatic amines,$N,N$-Dimethylaniline $(A)$ is more basic than $N$-Methylaniline $(D)$ and Aniline $(B)$ due to the electron-donating $+I$ effect of the two methyl groups,which increases electron density on the nitrogen atom. Thus,$A$ has the lowest $pK_b$ among the aromatics: $A-II$ $(8.92)$.$3$. $N$-Methylaniline $(D)$ is more basic than Aniline $(B)$ due to the $+I$ effect of one methyl group. Thus,$D-I$ $(9.30)$.$4$. Aniline $(B)$ is the least basic among these due to the resonance of the lone pair with the benzene ring. Thus,$B-III$ $(9.38)$.Therefore,the correct matching is $A-II, B-III, C-IV, D-I$.

List-$I$ (Amine)	List-$II$ ($pK_b$ value)
$A$. $N,N$-Dimethylaniline	$I$. $9.30$
$B$. Aniline	$II$. $8.92$
$C$. $N$-Ethylethanamine	$III$. $9.38$
$D$. $N$-Methylaniline	$IV$. $3.00$

Match the following:
List-$I$ (Amine) List-$II$ ($pK_b$ value)
$A$. $N,N$-Dimethylaniline $I$. $9.30$
$B$. Aniline $II$. $8.92$
$C$. $N$-Ethylethanamine $III$. $9.38$
$D$. $N$-Methylaniline $IV$. $3.00$

The correct answer is

Similar Questions

Which of the following statements is not true?

The major product $Z$ formed in the following sequence of reactions is:

Identify the product $B$ in the following reaction:
$C_6H_5NH_2$ $\xrightarrow[0^\circ-5^\circ C]{NaNO_2/HCl} A$ $\xrightarrow{Ph-N(CH_3)_2} B$

The product of this Hoffmann bromamide reaction is:

Identify the incorrect statements.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the following:List-$I$ (Amine)List-$II$ ($pK_b$ value)$A$. $N,N$-Dimethylaniline$I$. $9.30$$B$. Aniline$II$. $8.92$$C$. $N$-Ethylethanamine$III$. $9.38$$D$. $N$-Methylaniline$IV$. $3.00$The correct answer is