Match the following:List-IList-IIA. Aq. solut | vedclass

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Question

(A) $AlCl_3$ is a salt of a weak base and a strong acid; it undergoes cationic hydrolysis:$Al^{3+} + 3H_2O \rightarrow Al(OH)_3 + 3H^+$$H^+$ ions are

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$A-II, B-I, C-III, D-V$

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(A) $AlCl_3$ is a salt of a weak base and a strong acid; it undergoes cationic hydrolysis:$Al^{3+} + 3H_2O \rightarrow Al(OH)_3 + 3H^+$$H^+$ ions are released into the solution, making the aqueous solution of $AlCl_3$ acidic $(A-II)$.$CH_3COONa$ is a salt of a weak acid and a strong base; it undergoes anionic hydrolysis:$CH_3COO^- + H_2O \rightarrow CH_3COOH + OH^-$$OH^-$ ions are released, making the solution basic $(B-I)$.$KCl$ is a strong electrolyte and an ionic compound, making its aqueous solution highly conductive $(C-III)$.$Al_2O_3$ is an amphoteric oxide as it reacts with both acids and bases $(D-V)$.Therefore, the correct match is $A-II, B-I, C-III, D-V$.

List-$I$	List-$II$
$A$. $Aq.$ solution of $AlCl_3$	$I$. Basic
$B$. $Aq.$ solution of $CH_3COONa$	$II$. Acidic
$C$. $Aq.$ solution of $KCl$	$III$. Highly conductive
$D$. $Al_2O_3$	$IV$. Strongly basic
	$V$. Amphoteric

Match the following:
List-$I$ List-$II$
$A$. $Aq.$ solution of $AlCl_3$ $I$. Basic
$B$. $Aq.$ solution of $CH_3COONa$ $II$. Acidic
$C$. $Aq.$ solution of $KCl$ $III$. Highly conductive
$D$. $Al_2O_3$ $IV$. Strongly basic
$V$. Amphoteric

The correct match is:

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Match the following:List-$I$List-$II$$A$. $Aq.$ solution of $AlCl_3$$I$. Basic$B$. $Aq.$ solution of $CH_3COONa$$II$. Acidic$C$. $Aq.$ solution of $KCl$$III$. Highly conductive$D$. $Al_2O_3$$IV$. Strongly basic$V$. AmphotericThe correct match is: