Match the items of Column-$I$ and Column-$II$.
Column-$I$ Column-$II$ $A$. $S_N1$ reaction $1$. vic-dibromides $B$. Chemicals in fire extinguisher $2$. gem-dihalides $C$. Bromination of alkenes $3$. Racemisation $D$. Alkylidene halides $4$. Saytzeff rule $E$. Elimination of $HX$ from alkyl halide $5$. Chlorobromocarbons
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. $S_N1$ reaction | $1$. vic-dibromides |
| $B$. Chemicals in fire extinguisher | $2$. gem-dihalides |
| $C$. Bromination of alkenes | $3$. Racemisation |
| $D$. Alkylidene halides | $4$. Saytzeff rule |
| $E$. Elimination of $HX$ from alkyl halide | $5$. Chlorobromocarbons |
(A-3, B-5, C-1, D-2, E-4) $A-3, B-5, C-1, D-2, E-4$
$A$. $S_N1$ reactions proceed through the formation of a carbocation intermediate,which leads to the formation of a racemic mixture (Racemisation).
$B$. Chlorobromocarbons are commonly used as chemicals in fire extinguishers.
$C$. Bromination of alkenes involves the addition of bromine across the double bond to form vic-dibromides.
$D$. Alkylidene halides are also known as gem-dihalides,where two halogen atoms are attached to the same carbon atom.
$E$. The elimination of $HX$ from an alkyl halide follows the Saytzeff rule,which states that the more substituted alkene is the major product.
$A$. $S_N1$ reactions proceed through the formation of a carbocation intermediate,which leads to the formation of a racemic mixture (Racemisation).
$B$. Chlorobromocarbons are commonly used as chemicals in fire extinguishers.
$C$. Bromination of alkenes involves the addition of bromine across the double bond to form vic-dibromides.
$D$. Alkylidene halides are also known as gem-dihalides,where two halogen atoms are attached to the same carbon atom.
$E$. The elimination of $HX$ from an alkyl halide follows the Saytzeff rule,which states that the more substituted alkene is the major product.
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Similar Questions
In the given reaction,$[X]$ will be:
Difficult
View Solution$(Z)-2$-Butene reacts with $Br_2/H_2O$. The resulting bromohydrin when treated with methoxide in methanol undergoes an intramolecular $S_N2$ reaction. Taking into consideration the stereochemical consequences of the reaction mechanism involved, choose the final product$(s)$ of these transformations.
Match the type of reaction given in Column-$I$ with the reaction in Column-$II$.
Column-$I$ (Reactants) Column-$II$ (Type of Reaction) $(A)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 K} C_6H_5N_2^+X^-$ $(i)$ Wurtz-Fittig reaction $(B)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2} C_6H_5X$ $(ii)$ Diazotization $(C)$ $C_6H_6 + 2Na + RX \xrightarrow{\text{dry ether}} C_6H_5R$ $(iii)$ Sandmeyer reaction $(D)$ $2C_6H_6 + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5$ $(iv)$ Fittig reaction
| Column-$I$ (Reactants) | Column-$II$ (Type of Reaction) |
|---|---|
| $(A)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 K} C_6H_5N_2^+X^-$ | $(i)$ Wurtz-Fittig reaction |
| $(B)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2} C_6H_5X$ | $(ii)$ Diazotization |
| $(C)$ $C_6H_6 + 2Na + RX \xrightarrow{\text{dry ether}} C_6H_5R$ | $(iii)$ Sandmeyer reaction |
| $(D)$ $2C_6H_6 + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5$ | $(iv)$ Fittig reaction |
Medium
View SolutionComplete the following reactions:
$(1)$ Isopropyl bromide $\xrightarrow[{KOH, \Delta}]{{\text{alcoholic}}} X$ $\xrightarrow[{peroxide}]{{HBr}} Y$
$(2)$ $n$-propyl alcohol $\xrightarrow[{443 \ K}]{{\text{Conc. } H_2SO_4}} X$ $\xrightarrow{{HBr}} Y$
$(1)$ Isopropyl bromide $\xrightarrow[{KOH, \Delta}]{{\text{alcoholic}}} X$ $\xrightarrow[{peroxide}]{{HBr}} Y$
$(2)$ $n$-propyl alcohol $\xrightarrow[{443 \ K}]{{\text{Conc. } H_2SO_4}} X$ $\xrightarrow{{HBr}} Y$
Difficult
View SolutionAssertion : Alkylbenzene is not prepared by Friedel-Crafts alkylation of benzene.
Reason : Alkyl halides are less reactive than acyl halides.
Reason : Alkyl halides are less reactive than acyl halides.
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