Match the List-I with List-II:List-IList-IIA. | vedclass

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$(A)$ The ratio of specific heats is given by $\gamma = \frac{C_P}{C_V} = 1 + \frac{2}{f}$, where $f$ is the degree of freedom.For a triatomic rigid g

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$A-III, B-IV, C-I, D-II$

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$(A)$ The ratio of specific heats is given by $\gamma = \frac{C_P}{C_V} = 1 + \frac{2}{f}$, where $f$ is the degree of freedom.For a triatomic rigid gas, $f = 6$, so $\gamma = 1 + \frac{2}{6} = \frac{4}{3}$. $(A-III)$For a diatomic non-rigid gas, $f = 7$, so $\gamma = 1 + \frac{2}{7} = \frac{9}{7}$. $(B-IV)$For a monoatomic gas, $f = 3$, so $\gamma = 1 + \frac{2}{3} = \frac{5}{3}$. $(C-I)$For a diatomic rigid gas, $f = 5$, so $\gamma = 1 + \frac{2}{5} = \frac{7}{5}$. $(D-II)$Thus, the correct match is $A-III, B-IV, C-I, D-II$.

List-$I$	List-$II$
$A$. Triatomic rigid gas	$I$. $\frac{C_P}{C_V} = \frac{5}{3}$
$B$. Diatomic non-rigid gas	$II$. $\frac{C_P}{C_V} = \frac{7}{5}$
$C$. Monoatomic gas	$III$. $\frac{C_P}{C_V} = \frac{4}{3}$
$D$. Diatomic rigid gas	$IV$. $\frac{C_P}{C_V} = \frac{9}{7}$

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