The mean kinetic energy per degree of freedom of gas molecules is:

$A$ diatomic gas consisting of rigid molecules is at a temperature of $87^{\circ} C$. If the moment of inertia of the rotating diatomic rigid molecule is $2.76 \times 10^{-46} kg \cdot m^2$,then the rms angular speed of the molecule is (Boltzmann constant $= 1.38 \times 10^{-23} J \cdot K^{-1}$)

Consider two ideal diatomic gases $A$ and $B$ at some temperature $T$. Molecules of the gas $A$ are rigid,and have a mass $m$. Molecules of the gas $B$ have an additional vibrational mode,and have a mass $\frac{m}{4}$. The ratio of the specific heats $(C_{v}^{A}$ and $C_{v}^{B})$ of gas $A$ and $B$,respectively,is

$Assertion :$ For a gas atom,the number of degrees of freedom is $3$.
$Reason :$ $\frac{C_P}{C_V} = \gamma $

The ratio of specific heats at constant pressure and at constant volume is $\gamma$. To find out the degree of freedom,the expression is

State the law of equipartition of energy.