Methyl alcohol on oxidation with acidified K_ | vedclass

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Question

(C) Primary alcohols on oxidation with strong oxidizing agents like acidified $K_2Cr_2O_7$ are oxidized to carboxylic acids.Methyl alcohol $(CH_3OH)$

Vedclass · Accepted Answer

$HCOOH$

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(C) Primary alcohols on oxidation with strong oxidizing agents like acidified $K_2Cr_2O_7$ are oxidized to carboxylic acids.Methyl alcohol $(CH_3OH)$ is a primary alcohol.It undergoes oxidation to form formaldehyde $(HCHO)$,which is further oxidized to formic acid $(HCOOH)$.The reaction is: $CH_3OH$ $\xrightarrow{[O]} HCHO$ $\xrightarrow{[O]} HCOOH$.

Methyl alcohol on oxidation with acidified $K_2Cr_2O_7$ gives

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