$Methyl$ amine on reaction with chlorine in the presence of $NaOH$ gives:

$A$ compound $X$ with formula $C_4H_{11}N$ reacts with $HNO_2$ to liberate nitrogen and produce compound $Y$. The compound $Y$ on treatment with $I_2 / NaOH$ produces a sodium salt of a carboxylic acid. The compound $X$ is

Identify product $D$ in the following reaction sequence:
$CH_3-C(CH_3)_2-CH_2-CH_2-OH$ $\xrightarrow[H_2O, \text{heat}]{K_2Cr_2O_7, H_2SO_4} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{2(CH_3)_2NH} C$ $\xrightarrow[2. H_2O]{1. LiAlH_4, \text{diethyl ether}} D$

$H_3CCONH_2 + Br_2 + 4NaOH \longrightarrow Y + Na_2CO_3 + 2NaBr + 2H_2O$
What is $Y$ in the above reaction?

When an organic compound was treated with sodium nitrite and hydrochloric acid in the ice-cold condition,nitrogen gas was evolved copiously. The compound is

What is obtained from the hydrolysis of isocyanide?