Mohr salt is prepared from an equimolar solution of:

  • A
    $FeSO_4 \cdot 7 H_2O$ and $K_2SO_4$
  • B
    $FeSO_4 \cdot 7 H_2O$ and $(NH_4)_2SO_4$
  • C
    $CuSO_4 \cdot 5 H_2O$ and $K_2SO_4$
  • D
    $CuSO_4 \cdot 5 H_2O$ and $(NH_4)_2SO_4$

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