Molar concentration $(M)$ of any solution $=$
- A$\frac{\text{No. of moles of solute}}{\text{Volume of solution in litre}}$
- B$\frac{\text{No. of gram equivalent of solute}}{\text{Volume of solution in litre}}$
- C$\frac{\text{No. of moles of solute}}{\text{Mass of solvent in kg}}$
- D$\frac{\text{No. of moles of any constituent}}{\text{Total no. of moles of all constituents}}$
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$A$ $6.50$ molal solution of $KOH$ $(aq.)$ has a density of $1.89 \ g \ cm^{-3}$. The molarity of the solution is .......... $mol \ dm^{-3}$.
(Round off to the Nearest Integer).
[Atomic masses: $K = 39.0 \ u, O = 16.0 \ u, H = 1.0 \ u$]
(Round off to the Nearest Integer).
[Atomic masses: $K = 39.0 \ u, O = 16.0 \ u, H = 1.0 \ u$]
The number of moles of $NaOH$ in $2 \ L$ of $0.5 \ M \ NaOH$ solution is ..........
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