Molar heat capacity (C_p) of water at constan | vedclass

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(A) The formula for heat supplied at constant pressure is given by $q = n 	imes C_p 	imes \Delta T$. Given: Heat supplied $(q)$ = $1 \ kJ = 1000 \ J

Vedclass · Accepted Answer

$2.4$

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(A) The formula for heat supplied at constant pressure is given by $q = n 	imes C_p 	imes \Delta T$. Given: Heat supplied $(q)$ = $1 \ kJ = 1000 \ J$. Molar mass of water $(H_2O)$ = $18 \ g \ mol^{-1}$. Number of moles $(n)$ = $\frac{	ext{mass}}{	ext{molar mass}} = \frac{100 \ g}{18 \ g \ mol^{-1}} = \frac{100}{18} \ mol$. Molar heat capacity $(C_p)$ = $75 \ J \ K^{-1} \ mol^{-1}$. Substituting the values in the formula: $1000 = \frac{100}{18} 	imes 75 	imes \Delta T$. $\Delta T = \frac{1000 	imes 18}{100 	imes 75} = \frac{180}{75} = 2.4 \ K$.

Molar heat capacity $(C_p)$ of water at constant pressure is $75 \ J \ K^{-1} \ mol^{-1}$. The increase in temperature (in $K$) of $100 \ g$ of water when $1 \ kJ$ of heat is supplied to it is

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