Molar specific heat at constant volume,for a | vedclass

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Question

(A) For a non-linear triatomic gas molecule,the degrees of freedom $(f)$ are calculated as follows:$1$. Translational degrees of freedom: $3$ (along $

Vedclass · Accepted Answer

$3 R$

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(A) For a non-linear triatomic gas molecule,the degrees of freedom $(f)$ are calculated as follows:$1$. Translational degrees of freedom: $3$ (along $x, y, z$ axes).$2$. Rotational degrees of freedom: $3$ (since it is non-linear,it can rotate about three mutually perpendicular axes).$3$. Total degrees of freedom: $f = 3 + 3 = 6$.The molar specific heat at constant volume $(C_v)$ is given by the formula:$C_v = \frac{f}{2} R$Substituting $f = 6$ into the formula:$C_v = \frac{6}{2} R = 3 R$Therefore,the correct option is $A$.

Molar specific heat at constant volume,for a non-linear triatomic gas is (vibration mode neglected).

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Statement $A: C_P - C_V = R$
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