Molar specific heat of oxygen at constant pre | vedclass

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(C) Given: $C_p = 7.2 \, cal/mol \cdot K$,$R = 8.3 \, J/mol \cdot K$. Since $1 \, cal \approx 4.18 \, J$,we convert $R$ to $cal$: $R = 8.3 / 4.18 \app

Vedclass · Accepted Answer

$250$

Vedclass · Answer

(C) Given: $C_p = 7.2 \, cal/mol \cdot K$,$R = 8.3 \, J/mol \cdot K$. Since $1 \, cal \approx 4.18 \, J$,we convert $R$ to $cal$: $R = 8.3 / 4.18 \approx 2 \, cal/mol \cdot K$.Molar heat capacity at constant volume is given by $C_v = C_p - R$.$C_v = 7.2 - 2 = 5.2 \, cal/mol \cdot K \approx 5 \, cal/mol \cdot K$.Number of moles $n = 5 \, mol$.Change in temperature $\Delta T = 20^\circ C - 10^\circ C = 10 \, K$.The heat required at constant volume is $\Delta Q = n C_v \Delta T$.$\Delta Q = 5 	imes 5 	imes 10 = 250 \, cal$.

Molar specific heat of oxygen at constant pressure $C_p = 7.2 \, cal/mol \cdot ^\circ C$ and $R = 8.3 \, J/mol \cdot K$. At constant volume,$5 \, mol$ of oxygen is heated from $10^\circ C$ to $20^\circ C$. The quantity of heat required is approximately ........ $cal$.

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