The molecular formula of the pentahydroxy aci | vedclass

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Question

(A) Glucose $(C_6H_{12}O_6)$ contains an aldehyde group $(-CHO)$ and five hydroxyl groups $(-OH)$.When glucose is oxidized with bromine water ($Br_2$

Vedclass · Accepted Answer

$C_6H_{12}O_7$

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(A) Glucose $(C_6H_{12}O_6)$ contains an aldehyde group $(-CHO)$ and five hydroxyl groups $(-OH)$.When glucose is oxidized with bromine water ($Br_2$ water),the aldehyde group is selectively oxidized to a carboxylic acid group $(-COOH)$ while the hydroxyl groups remain unaffected.This reaction produces gluconic acid,which has the molecular formula $C_6H_{12}O_7$.Since it contains five hydroxyl groups and one carboxylic acid group,it is a pentahydroxy acid.

The molecular formula of the pentahydroxy acid obtained when glucose is oxidized with $Br_2$ water is:

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