Class 11PhysicsSystem of Particles and Rotational MotionMoment of Inertia of Compound Bodies and Theorem of Moment of Inertia
MediumThe moment of inertia of a disc of mass $M$ and radius $R$ about any of its diameters is $\frac{MR^2}{4}$. The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be $\frac{x}{2} MR^2$. The value of $x$ is $..........$.
- A$1.5$
- B$6$
- C$9$
- D$3$
Explore More
Similar Questions
The moment of inertia of a square plate of side $l$ and mass $M$ about an axis passing through one of its corners and perpendicular to the plane of the square plate is given by:
DifficultJEE MAIN 2021
View SolutionThe moment of inertia of a solid sphere of mass $M$ and radius $R$ about its tangent is:
Easy
View SolutionThe figure shows three identical discs,each of mass $M$ and radius $R$. Find the moment of inertia of this system about the axis $xx'$.
Difficult
View SolutionThe moment of inertia of a circular ring about an axis perpendicular to its plane and passing through its center is $200 \, gm \cdot cm^2$. The moment of inertia about its diameter is ....... $gm \cdot cm^2$.
Medium
View SolutionThe moment of inertia of a solid cylinder about its own axis is the same as its moment of inertia about an axis passing through its centre of gravity and perpendicular to its length. The relation between its length $L$ and radius $R$ is
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo