Monochromatic light of frequency 6 times 10^{ | vedclass

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(C) The power $P$ emitted by a source is given by the product of the number of photons emitted per second $(n)$ and the energy of a single photon $(E

Vedclass · Accepted Answer

$5 	imes 10^{15}$

Vedclass · Answer

(C) The power $P$ emitted by a source is given by the product of the number of photons emitted per second $(n)$ and the energy of a single photon $(E = h
u)$.$P = n h 
u$Rearranging for $n$:$n = \frac{P}{h 
u}$Given values:$P = 2 	imes 10^{-3} \,W$$h = 6.63 	imes 10^{-34} \,Js$$
u = 6 	imes 10^{14} \,Hz$Substituting the values:$n = \frac{2 	imes 10^{-3}}{6.63 	imes 10^{-34} 	imes 6 	imes 10^{14}}$$n = \frac{2 	imes 10^{-3}}{39.78 	imes 10^{-20}}$$n = \frac{2}{39.78} 	imes 10^{17} \approx 0.05027 	imes 10^{17} = 5.027 	imes 10^{15} \approx 5 	imes 10^{15}$Thus, the number of photons emitted per second is $5 	imes 10^{15}$.

Monochromatic light of frequency $6 \times 10^{14} \,Hz$ is produced by a laser. The power emitted is $2 \times 10^{-3} \,W$. How many photons per second on an average are emitted by the source? (Given $h = 6.63 \times 10^{-34} \,Js$)

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