Monochromatic light of frequency 6 times 10^{ | vedclass

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(D) The energy of a photon is given by the formula $E = h 
u$,where $h$ is Planck's constant $(6.63 	imes 10^{-34} \,J \cdot s)$ and $
u$ is the fr

Vedclass · Accepted Answer

$2.5$

Vedclass · Answer

(D) The energy of a photon is given by the formula $E = h 
u$,where $h$ is Planck's constant $(6.63 	imes 10^{-34} \,J \cdot s)$ and $
u$ is the frequency of the light.Given: $
u = 6 	imes 10^{14} \,Hz$.Substituting the values: $E = (6.63 	imes 10^{-34} \,J \cdot s) 	imes (6 	imes 10^{14} \,Hz) = 3.978 	imes 10^{-19} \,J$.To convert the energy from Joules to electron-volts $(eV)$,we divide by the charge of an electron $(1.6 	imes 10^{-19} \,C)$:$E = \frac{3.978 	imes 10^{-19} \,J}{1.6 	imes 10^{-19} \,J/eV} \approx 2.486 \,eV$.Rounding to the nearest value,we get $E \approx 2.5 \,eV$.

Monochromatic light of frequency $6 \times 10^{14} \,Hz$ is produced by a laser. The power emitted is $2 \times 10^{-3} \,W$. The energy of the photon in this light beam is . . . . . . eV.

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