Xenon tetrafluoride,XeF_4 is: | vedclass

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(B) The structure of $XeF_4$ is square planar due to the presence of two lone pairs on the central $Xe$ atom,which occupy the axial positions to minim

Vedclass · Accepted Answer

$B$. Square planar and acts as a fluoride donor with $PF_5$

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(B) The structure of $XeF_4$ is square planar due to the presence of two lone pairs on the central $Xe$ atom,which occupy the axial positions to minimize repulsion.$XeF_4$ acts as a fluoride donor when it reacts with strong Lewis acids like $SbF_5$,$PF_5$,or $AsF_5$ to form $[XeF_3]^+$ and $[MF_6]^-$ ions.Specifically,$XeF_4 + SbF_5 \rightarrow [XeF_3]^+[SbF_6]^-$.Among the given options,$B$ correctly identifies the geometry as square planar and the property of acting as a fluoride donor with Lewis acids like $PF_5$.

Column-$I$	Column-$II$
$(a)$ $XeF_4$	$(i)$ pyramidal
$(b)$ $XeF_6$	(ii) square planar
$(c)$ $XeOF_4$	(iii) distorted octahedral
$(d)$ $XeO_3$	(iv) square pyramidal

Xenon tetrafluoride,$XeF_4$ is:

Similar Questions

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Column-$I$ Column-$II$
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$(c)$ $XeOF_4$ (iii) distorted octahedral
$(d)$ $XeO_3$ (iv) square pyramidal

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