Normal maize has starchy seeds which remain s | vedclass

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(B) $1$. The trait for smooth seeds is dominant over the trait for crinkled (sugary) seeds.$2$. Let the dominant allele for smooth seeds be $S$ and th

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$3$ smooth : $1$ sugary

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(B) $1$. The trait for smooth seeds is dominant over the trait for crinkled (sugary) seeds.$2$. Let the dominant allele for smooth seeds be $S$ and the recessive allele for crinkled seeds be $s$.$3$. The cross between a mutant (homozygous recessive,$ss$) and a normal plant (homozygous dominant,$SS$) produces an $F_1$ generation with the genotype $Ss$,which expresses the dominant smooth phenotype.$4$. When the $F_1$ $(Ss)$ is allowed to self-pollinate $(Ss 	imes Ss)$,the offspring follow the Mendelian monohybrid ratio.$5$. The Punnett square for $Ss 	imes Ss$ results in genotypes: $1 SS : 2 Ss : 1 ss$.$6$. Phenotypically,this corresponds to $3$ smooth seeds ($SS$ and $Ss$) and $1$ crinkled (sugary) seed $(ss)$.$7$. Therefore,the ratio is $3$ smooth : $1$ sugary.

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