Not considering the electronic spin,the degen | vedclass

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Question

(C) For a multi-electron species like $H^-$,the electronic configuration is $1s^2$. Ground state: $1s^2$. First excited state: One electron is promote

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) For a multi-electron species like $H^-$,the electronic configuration is $1s^2$. Ground state: $1s^2$. First excited state: One electron is promoted to the next available orbital,$1s^1 2s^1$. Second excited state: One electron is promoted to the $2p$ subshell,$1s^1 2p^1$. The $2p$ subshell consists of three degenerate orbitals $(2p_x, 2p_y, 2p_z)$. Since the $1s$ electron is fixed,the degeneracy is determined by the number of available $2p$ orbitals,which is $3$.

Not considering the electronic spin,the degeneracy of the second excited state $(n=3)$ of $H$ atom is $9$,while the degeneracy of the second excited state of $H^{-}$ is

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