Nucleus $A$ has a mass number of $220$ and its binding energy per nucleon is $5.6 \, MeV$. It splits into two fragments '$B$' and '$C$' with mass numbers $105$ and $115$,respectively. The binding energy per nucleon for both '$B$' and '$C$' is $6.4 \, MeV$. The energy $Q$ released per fission will be............$MeV$.

  • A
    $0.8$
  • B
    $275$
  • C
    $220$
  • D
    $176$

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The electrostatic energy of $Z$ protons uniformly distributed throughout a spherical nucleus of radius $R$ is given by $E = \frac{3}{5} \frac{Z(Z-1) e^2}{4 \pi \varepsilon_0 R}$. The measured masses of the neutron,${ }_1^1 H$,${ }_7^{15} N$,and ${ }_8^{15} O$ are $1.008665 \ u$,$1.007825 \ u$,$15.000109 \ u$,and $15.003065 \ u$,respectively. Given that the radii of both the ${ }_7^{15} N$ and ${ }_8^{15} O$ nuclei are the same,$1 \ u = 931.5 \ MeV/c^2$ ($c$ is the speed of light),and $e^2 / (4 \pi \varepsilon_0) = 1.44 \ MeV \ fm$. Assuming that the difference between the binding energies of ${ }_7^{15} N$ and ${ }_8^{15} O$ is purely due to the electrostatic energy,the radius of either of the nuclei is $(1 \ fm = 10^{-15} \ m)$: (in $fm$)

The mass defect for the nucleus of helium is $0.0303 \, a.m.u.$ What is the binding energy per nucleon for helium in $MeV$?

The mass of a proton is $1.0073 \, u$ and that of a neutron is $1.0087 \, u$. The binding energy of $_2He^4$ is .... ($u = \text{atomic mass unit}$,mass of helium nucleus = $4.0015 \, u$)

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What is the energy equivalent to one kilogram of mass?

Binding energy of a nucleus is

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