Number of pi electrons in cyclobutadienyl ani | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The cyclobutadienyl anion $({C_4}{H_4})^{2-}$ consists of a four-membered ring with two double bonds and two negative charges on the carbons.Each

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(D) The cyclobutadienyl anion $({C_4}{H_4})^{2-}$ consists of a four-membered ring with two double bonds and two negative charges on the carbons.Each double bond contributes $2$ $\pi$ electrons,totaling $4$ $\pi$ electrons.The two negative charges each represent a lone pair of electrons in a $p$-orbital,which also participate in the $\pi$ system.Therefore,total $\pi$ electrons $= 4 	ext{ (from double bonds)} + 2 	imes 2 	ext{ (from negative charges)} = 8$ $\pi$ electrons.Thus,the correct option is $D$.

Number of $\pi$ electrons in cyclobutadienyl anion $({C_4}{H_4})^{2-}$ is

Similar Questions

How many lone pairs of electrons are present in a hydroxyl ion?

Among the following molecules,the $N-Si$ bond length is shortest in:

Which of the following pairs of molecules is isoelectronic as well as isostructural?

In the electronic structure of $H_2SO_4$,the total number of unshared electrons is

Among the molecules $O_2$,$KO_2$,$H_2O_2$,$F_2O_2$ and $BaO_2$,the pair that has the most similar oxygen-oxygen bond length is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module