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Question

(B) During aerobic respiration,$1$ molecule of pyruvic acid undergoes the following steps:$1$. Link reaction: $1$ $NADH$ is produced.$2$. Krebs cycle:

Vedclass · Accepted Answer

$42$

Vedclass · Answer

(B) During aerobic respiration,$1$ molecule of pyruvic acid undergoes the following steps:$1$. Link reaction: $1$ $NADH$ is produced.$2$. Krebs cycle: $4$ $NADH$,$1$ $FADH_2$,and $1$ $GTP$ $(ATP)$ are produced.Total per pyruvic acid: $5$ $NADH$ and $1$ $FADH_2$.For $3$ pyruvic acid molecules: $15$ $NADH$ and $3$ $FADH_2$.Oxidative phosphorylation involves the electron transport system $(ETS)$ where $1$ $NADH$ yields $3$ $ATP$ and $1$ $FADH_2$ yields $2$ $ATP$.Total $ATP$ from $NADH = 15 	imes 3 = 45$.Total $ATP$ from $FADH_2 = 3 	imes 2 = 6$.Total $ATP$ via oxidative phosphorylation = $45 + 6 = 51$.However,if we consider the standard $P$/$O$ ratio where $1$ $NADH = 2.5$ $ATP$ and $1$ $FADH_2 = 1.5$ $ATP$:Total $ATP = (15 	imes 2.5) + (3 	imes 1.5) = 37.5 + 4.5 = 42$.Given the options,$42$ is the correct value based on the modern $P$/$O$ ratio.

Number of $ATP$ molecules synthesized through oxidative phosphorylation during aerobic respiration of $3$ pyruvic acid molecules are

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