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(D) To determine the number of bonding electron pairs and lone pairs,we look at the central atom of each molecule:$1$. In $ClF_3$: The central atom $C

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$3,2 ; 4,1 ; 5,1$

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(D) To determine the number of bonding electron pairs and lone pairs,we look at the central atom of each molecule:$1$. In $ClF_3$: The central atom $Cl$ is bonded to $3$ $F$ atoms (bonding pairs = $3$) and has $2$ lone pairs on the $Cl$ atom (lone pairs = $2$).$2$. In $SF_4$: The central atom $S$ is bonded to $4$ $F$ atoms (bonding pairs = $4$) and has $1$ lone pair on the $S$ atom (lone pairs = $1$).$3$. In $BrF_5$: The central atom $Br$ is bonded to $5$ $F$ atoms (bonding pairs = $5$) and has $1$ lone pair on the $Br$ atom (lone pairs = $1$).Thus,the number of bonding pairs and lone pairs are $3,2$; $4,1$; and $5,1$ respectively.

Number of bonding electron pairs and number of lone pairs of electrons in $ClF_3$,$SF_4$,$BrF_5$ respectively are

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Observe the following statements:
$i$. According to $\text{VSEPR}$ theory,$ClF_3$ and $SO_2$ are shown as $AB_3E_2$ and $AB_2E$ type molecules respectively.
$ii$. $SF_4$ has a "See-saw" shape.
$iii$. $HgCl_2$ and $PbCl_2$ have the same shape.
The statements which are not correct are:

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