Number of hydrogen ions present in 10 million | vedclass

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(C) The $10$ millionth part is equivalent to $10^{-7}$.$	herefore$ The volume of the part is $1.33 \ cm^{3} 	imes 10^{-7} = 1.33 	imes 10^{-7} \ mL

Vedclass · Accepted Answer

$8.01$ million

Vedclass · Answer

(C) The $10$ millionth part is equivalent to $10^{-7}$.$	herefore$ The volume of the part is $1.33 \ cm^{3} 	imes 10^{-7} = 1.33 	imes 10^{-7} \ mL$.For pure water at $25^{\circ} C$, $[H^{+}] = 10^{-7} \ mol/L$.Since $1 \ L = 1000 \ mL$, $1 \ mL$ of water contains $10^{-7} / 1000 = 10^{-10} \ mol$ of $H^{+}$ ions.Therefore, the number of moles of $H^{+}$ in $1.33 	imes 10^{-7} \ mL$ is $1.33 	imes 10^{-7} 	imes 10^{-10} = 1.33 	imes 10^{-17} \ mol$.Number of $H^{+}$ ions $= 	ext{moles} 	imes N_{A} = 1.33 	imes 10^{-17} 	imes 6.022 	imes 10^{23}$.$= 8.009 	imes 10^{6} \approx 8.01 	imes 10^{6}$ or $8.01$ million.

Number of hydrogen ions present in $10$ millionth part of $1.33 \ cm^{3}$ of pure water at $25^{\circ} C$ is

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