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(B) The reactant is $1,4$-dimethylcyclohex-$1$-ene. The addition of $HBr$ to the double bond follows Markovnikov's rule. The double bond is between $C

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$2$

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(B) The reactant is $1,4$-dimethylcyclohex-$1$-ene. The addition of $HBr$ to the double bond follows Markovnikov's rule. The double bond is between $C_1$ and $C_2$. Upon protonation of the double bond,a carbocation is formed at $C_1$ (tertiary) or $C_2$ (secondary). The tertiary carbocation at $C_1$ is more stable. Since the molecule has a chiral center at $C_4$,the addition of $Br^-$ to the carbocation at $C_1$ creates a new chiral center at $C_1$. This results in the formation of two diastereomers (cis and trans isomers) because the methyl group at $C_4$ is already present. Therefore,$2$ products are formed.

How many products are formed in the following reaction?
$1,4$-dimethylcyclohex-$1$-ene + $HBr \rightarrow$ ?

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How many products are formed in the following reaction? $1,4$-dimethylcyclohex-$1$-ene + $HBr \rightarrow$ ?