Number of sigma bonds in P_4O_{10} is | vedclass

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(D) The structure of $P_4O_{10}$ consists of a $P_4$ tetrahedron where each edge is bridged by an oxygen atom ($P-O-P$ bonds). There are $6$ such $P-O

Vedclass · Accepted Answer

$16$

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(D) The structure of $P_4O_{10}$ consists of a $P_4$ tetrahedron where each edge is bridged by an oxygen atom ($P-O-P$ bonds). There are $6$ such $P-O-P$ bridges,contributing $12$ sigma bonds. Additionally,each of the $4$ phosphorus atoms is bonded to a terminal oxygen atom via a double bond $(P=O)$. Each $P=O$ bond consists of $1$ sigma bond and $1$ pi bond. Thus,there are $4$ sigma bonds from the $P=O$ groups. Total number of sigma bonds = $12$ (from $P-O-P$ bridges) + $4$ (from $P=O$ bonds) = $16$ sigma bonds.

Number of sigma bonds in $P_4O_{10}$ is

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