Observe the following Ellingham diagram,and i | vedclass

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(C) In an Ellingham diagram,the metal whose oxide line is lower can reduce the oxide of the metal whose line is higher.At point $A$ $(1673 \ K)$,the l

Vedclass · Accepted Answer

Below $1673 \ K$,$Al$ can reduce $MgO$ to $Mg$.

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(C) In an Ellingham diagram,the metal whose oxide line is lower can reduce the oxide of the metal whose line is higher.At point $A$ $(1673 \ K)$,the lines for the formation of $MgO$ and $Al_2O_3$ intersect,meaning $\Delta G^{\circ} = 0$ for the reaction $3MgO + 2Al \rightarrow Al_2O_3 + 3Mg$.Below $1673 \ K$,the $MgO$ line is below the $Al_2O_3$ line,so $Mg$ can reduce $Al_2O_3$ to $Al$.Above $1673 \ K$,the $Al_2O_3$ line is below the $MgO$ line,so $Al$ can reduce $MgO$ to $Mg$.Therefore,the statement that $Al$ can reduce $MgO$ to $Mg$ below $1673 \ K$ is incorrect.

Observe the following Ellingham diagram,and identify the incorrect statement regarding it.

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