Observe the following reactions (not balanced | vedclass

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(A) The first reaction is: $4BF_3 + 3LiAlH_4 \xrightarrow{(C_2H_5)_2O} 2B_2H_6 + 3LiF + 3AlF_3$. Here, $X$ is $B_2H_6$ (diborane).The second reaction

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It is a good oxidizing agent

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(A) The first reaction is: $4BF_3 + 3LiAlH_4 \xrightarrow{(C_2H_5)_2O} 2B_2H_6 + 3LiF + 3AlF_3$. Here, $X$ is $B_2H_6$ (diborane).The second reaction is: $B_2H_6 + 2NaH \longrightarrow 2NaBH_4$. Here, $Y$ is $NaBH_4$ (sodium borohydride).$NaBH_4$ contains the $BH_4^-$ ion, where hydrogen is in the $-1$ oxidation state.$NaBH_4$ is a well-known reducing agent, not an oxidizing agent.Therefore, the statement 'It is a good oxidizing agent' is incorrect.

Observe the following reactions (not balanced):
$BF_3 + LiAlH_4 \xrightarrow{(C_2H_5)_2O} X + LiF + AlF_3$
$X + NaH \longrightarrow Y$
The incorrect statement about $Y$ is:

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Observe the following reactions (not balanced):$BF_3 + LiAlH_4 \xrightarrow{(C_2H_5)_2O} X + LiF + AlF_3$$X + NaH \longrightarrow Y$The incorrect statement about $Y$ is: