Observe the following reactions: AB_{(g)} + 2 | vedclass

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(A) Enthalpy of dilution is the enthalpy change when a solution is diluted from one concentration to another. The given reactions are: $1) \ AB_{(g)}

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$(y-x)$

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(A) Enthalpy of dilution is the enthalpy change when a solution is diluted from one concentration to another. The given reactions are: $1) \ AB_{(g)} + 25 H_2O_{(l)} \rightarrow AB_{(25 H_2O)} ; \Delta H = x \ kJ \ mol^{-1}$ $2) \ AB_{(g)} + 50 H_2O_{(l)} \rightarrow AB_{(50 H_2O)} ; \Delta H = y \ kJ \ mol^{-1}$ To find the enthalpy of dilution for the process $AB_{(25 H_2O)} + 25 H_2O_{(l)} \rightarrow AB_{(50 H_2O)}$,we subtract equation $(1)$ from equation $(2)$: $\Delta H_{dil} = \Delta H_2 - \Delta H_1 = (y - x) \ kJ \ mol^{-1}$.

Observe the following reactions:
$AB_{(g)} + 25 H_2O_{(l)} \rightarrow AB_{(25 H_2O)} ; \Delta H = x \ kJ \ mol^{-1}$
$AB_{(g)} + 50 H_2O_{(l)} \rightarrow AB_{(50 H_2O)} ; \Delta H = y \ kJ \ mol^{-1}$
The enthalpy of dilution $(\Delta H_{dil})$ in $kJ \ mol^{-1}$ is

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Observe the following reactions: $AB_{(g)} + 25 H_2O_{(l)} \rightarrow AB_{(25 H_2O)} ; \Delta H = x \ kJ \ mol^{-1}$ $AB_{(g)} + 50 H_2O_{(l)} \rightarrow AB_{(50 H_2O)} ; \Delta H = y \ kJ \ mol^{-1}$ The enthalpy of dilution $(\Delta H_{dil})$ in $kJ \ mol^{-1}$ is