(C) $SbCl_2$ does not exist because $V^{th}$ group elements (Group $15$) typically exhibit $+3$ and $+5$ oxidation states. $Sb$ in $SbCl_2$ would be i

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(C) $SbCl_2$ does not exist because $V^{th}$ group elements (Group $15$) typically exhibit $+3$ and $+5$ oxidation states. $Sb$ in $SbCl_2$ would be in the $+2$ oxidation state,which is not a stable or common oxidation state for elements of this group.