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(B) The average intensity $I$ of an electromagnetic wave is related to the amplitude of the magnetic field $B_0$ by the formula: $I = \frac{B_0^2 C}{2

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$4 	imes 10^{-6} 	ext{ T}$

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(B) The average intensity $I$ of an electromagnetic wave is related to the amplitude of the magnetic field $B_0$ by the formula: $I = \frac{B_0^2 C}{2 \mu_0}$.Given,$I = \frac{6}{\pi} 	imes 10^3 	ext{ W/m}^2$,$C = 3 	imes 10^8 	ext{ m/s}$,and $\mu_0 = 4\pi 	imes 10^{-7} 	ext{ T m/A}$.Rearranging the formula for $B_0^2$: $B_0^2 = \frac{2 \mu_0 I}{C}$.Substituting the values: $B_0^2 = \frac{2 	imes (4\pi 	imes 10^{-7}) 	imes (\frac{6}{\pi} 	imes 10^3)}{3 	imes 10^8}$.Simplifying the expression: $B_0^2 = \frac{8\pi 	imes 10^{-7} 	imes 6 	imes 10^3}{\pi 	imes 3 	imes 10^8} = \frac{48 	imes 10^{-4}}{3 	imes 10^8} = 16 	imes 10^{-12}$.Taking the square root: $B_0 = \sqrt{16 	imes 10^{-12}} = 4 	imes 10^{-6} 	ext{ T}$.

On a particular day,the sun delivers an average power of $\left(\frac{6}{\pi} \times 10^3\right) \frac{W}{m^2}$ to the top of Earth's atmosphere. Find the amplitude of the magnetic field for the electromagnetic waves above the atmosphere. (Take $\mu_0 = 4\pi \times 10^{-7} \text{ SI units}$)

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