On mixing an alkane with chlorine and irradia | vedclass

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(D) The reaction of an alkane with chlorine in the presence of ultra-violet light is a free radical substitution reaction.For an alkane to form only o

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Neopentane

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(D) The reaction of an alkane with chlorine in the presence of ultra-violet light is a free radical substitution reaction.For an alkane to form only one mono-chloro-alkane, all the hydrogen atoms in the alkane must be equivalent.In $Neopentane$ $(2,2-dimethylpropane)$, all $12$ hydrogen atoms are attached to equivalent primary carbon atoms.Therefore, replacing any one of these hydrogen atoms with a chlorine atom results in the same product, $1-chloro-2,2-dimethylpropane$.

On mixing an alkane with chlorine and irradiating with ultra-violet light, it forms only one mono-chloro-alkane. The alkane is

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