On passing 3 A of electricity for 50 minute | vedclass

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(C) According to Faraday's first law of electrolysis,the mass of the substance deposited $(W)$ is given by the formula: $W = \frac{E 	imes I 	imes t

Vedclass · Accepted Answer

$19.3$

Vedclass · Answer

(C) According to Faraday's first law of electrolysis,the mass of the substance deposited $(W)$ is given by the formula: $W = \frac{E 	imes I 	imes t}{96500}$ Here,$W = 1.8 \ g$,$I = 3 \ A$,and $t = 50 \ minutes = 50 	imes 60 \ seconds = 3000 \ s$. Substituting the values into the formula: $1.8 = \frac{E 	imes 3 	imes 3000}{96500}$ Rearranging to solve for the equivalent mass $(E)$: $E = \frac{1.8 	imes 96500}{3 	imes 3000} = \frac{173700}{9000} = 19.3$ Therefore,the equivalent mass of the metal is $19.3$.

On passing $3 \ A$ of electricity for $50 \ minutes$,$1.8 \ g$ of metal deposits. The equivalent mass of the metal is:

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