One gas bleaches the colour of flowers by red | vedclass

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(D) $SO_2$ bleaches the colour of flowers by reduction,whereas $Cl_2$ bleaches by oxidation.$Cl_2$ reacts with water to produce nascent oxygen,which a

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$SO_2$ and $Cl_2$

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(D) $SO_2$ bleaches the colour of flowers by reduction,whereas $Cl_2$ bleaches by oxidation.$Cl_2$ reacts with water to produce nascent oxygen,which acts as an oxidizing agent to bleach the colour:$Cl_2 + H_2O \rightarrow 2HCl + [O]$$SO_2$ reacts with water to produce nascent hydrogen,which acts as a reducing agent to remove oxygen from the coloured substance,making it colourless:$SO_2 + 2H_2O \rightarrow H_2SO_4 + 2[H]$

One gas bleaches the colour of flowers by reduction while the other by oxidation,the two gases respectively are

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